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直线到圆的射影变换

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hbghlyj 发表于 2023-5-22 22:43 |阅读模式
在$\mathbb CP^1$上$z\mapsto z^{-1}$将直线$z+\bar z=1$映射到圆$z^{-1}+\bar z^{-1}=1$
问题:在$\mathbb RP^2$上有直线到圆的射影变换吗(需要是$\mathbb RP^2\to\mathbb RP^2$双射)

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 楼主| hbghlyj 发表于 2023-5-22 22:45
问题来源:
我在proj21.pdf page 16看到
Nonsingular conics actually have a very nice description. If we fix a point $x$ on the conic, and take a projective line not containing $x$, then projection from $x$ onto the line actually sets up a bijection between the conic and the line.
If $\mathbb F =\mathbb C$, this in fact defines a homeomorphism between the conic and the projective line, and hence the Riemann sphere, though of course this is not a projective equivalence

发现这帖取的$\varphi$有问题

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Czhang271828 发表于 2023-5-22 22:57
不行. $\mathbb P_{\mathbb R}^2$ 去掉一条直线后还是道路连通空间, 去掉一个圆后有两个连通分支.

所谓的极限情形是个抛物线.

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 楼主| hbghlyj 发表于 2023-5-22 23:09
Czhang271828 发表于 2023-5-22 15:57
不行. $\mathbb P_{\mathbb R}^2$ 去掉一条直线后还是道路连通空间, 去掉一个圆后有两个连通分支.

所谓的极限情形是个抛物线.


刚才想起: 射影变换是collineation(保持共线性)

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 楼主| hbghlyj 发表于 2023-5-22 23:10
hbghlyj 发表于 2023-5-22 15:43
在$\mathbb CP^1$上$z\mapsto z^{-1}$将直线$z+\bar z=1$映射到圆$z^{-1}+\bar z^{-1}=1$

哦, 我明白了:
因为整个$\mathbb CP^1$就是一射影直线, 无论怎么变换都“保持共线性”
$z\mapsto1/\bar z$保持共线性(collineation)且不是射影变换(homography)
The operation of taking the complex conjugate in the complex plane amounts to a reflection in the real line.
With the notation $z^∗$ for the conjugate of $z$, an anti-homography is given by
$$ f(z)={\frac {az^{*}+b}{cz^{*}+d}}. $$
Thus an anti-homography is the composition of conjugation with a homography, and so is an example of a collineation which is not an homography. For example, geometrically, the mapping $ f(z)=1/z^{*} $ amounts to circle inversion. The transformations of inversive geometry of the plane are frequently described as the collection of all homographies and anti-homographies of the complex plane.
Semilinear map
As mentioned by Blaschke and Klein, Michel Chasles preferred the term homography to collineation. A distinction between the terms arose when the distinction was clarified between the real projective plane and the complex projective line. Since there are no non-trivial field automorphisms of the real number field, all the collineations are homographies in the real projective plane, however due to the field automorphism of complex conjugation, not all collineations of the complex projective line are homographies. In applications such as computer vision where the underlying field is the real number field, homography and collineation can be used interchangeably.

Line-preserving transformations
A transformation of a projective plane which preserves lines is called a collineation. In every projective plane, a projective transformation will be a collineation. In the common Euclidean plane with the real numbers as the underlying field, the converse can be shown as well: every collineation is a projective transformation. If the underlying field has a non-trivial automorphism, the way the complex numbers do, this is no longer true. For example, one can compute the complex conjugate of every coordinate, thus preserving lines although that operation is not a projective transformation.

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 楼主| hbghlyj 发表于 2023-5-22 23:35
Czhang271828 发表于 2023-5-22 15:57
所谓的极限情形是个抛物线.


去掉一个抛物线还是有两个连通分支吧

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 楼主| hbghlyj 发表于 2023-5-22 23:37
hbghlyj 发表于 2023-5-22 15:45
发现这帖取的$\varphi$有问题


那个帖子是否已作废有办法补救吗

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 楼主| hbghlyj 发表于 2023-5-23 01:34
hbghlyj 发表于 2023-5-22 16:10
哦, 我明白了:
因为整个$\mathbb CP^1$就是一射影直线, 无论怎么变换都“保持共线性”
$z\mapsto1/\bar z$ ...

$\mathbb R^2$的直线对应到$\mathbb CP^1$就不是直线了.

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 楼主| hbghlyj 发表于 2023-5-26 17:45
Czhang271828 发表于 2023-5-22 15:57
不行. $\mathbb P_{\mathbb R}^2$ 去掉一条直线后还是道路连通空间, 去掉一个圆后有两个连通分支.

所谓的 ...


在$\Bbb RP^3$以$[0:0:1:1]$为中心的steorographic projection$$[x,y,z,t]\mapsto[x:y:0:t-z]$$它是单位球面$x^2+y^2+z^2=t^2$到平面$z=0$的射影变换

在$\Bbb RP^4$是否有单位球面到超平面的射影变换

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 楼主| hbghlyj 发表于 2023-6-4 04:07
hbghlyj 发表于 2023-5-22 16:37
那个帖子是否已作废有办法补救吗

我已经通过限制 $\varphi$ 的定义域在 $C$ 上来补救

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 楼主| hbghlyj 发表于 2023-6-4 04:10
射影变换首先是同胚的,去除一点的圆同胚于直线

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