Forgot password?
 Create new account
Search
View: 68|Reply: 1

[不等式] 一个多元不等式

[Copy link]

399

Threads

993

Posts

110K

Credits

Credits
11140

Show all posts

lemondian Post time 2023-11-10 17:27 |Read mode
给定正整数$m\geqslant 2,n\geqslant 2,x_k>0,k=1,2,\cdots ,n$,证明或否定:
$\sum_{k=1}^mx^n_k\sum_{k=1}^m\dfrac{1}{x^n_k}-m^2\geqslant (\dfrac{n}{n-1})^2(\sum_{k=1}^mx^{n-1}_k\sum_{k=1}^m\dfrac{1}{x^{n-1}_k}-m^2)$

399

Threads

993

Posts

110K

Credits

Credits
11140

Show all posts

 Author| lemondian Post time 2023-11-14 09:00
Help

手机版|悠闲数学娱乐论坛(第3版)

2025-3-6 17:03 GMT+8

Powered by Discuz!

× Quick Reply To Top Return to the list