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$$\frac{a}{\sin20^\circ}=\frac{b}{\sin60^\circ}=\frac{1}{\sin100^\circ}$$
令 $\theta=10^\circ$ 则
$$a=\frac{\sin2\theta}{\cos\theta},b=\frac{\sqrt{3}}{2\cos\theta}$$
$$\begin{align*}
\frac1a-b
&=\frac{\cos\theta}{\sin2\theta}-\frac{\sqrt{3}}{2\cos\theta}\\
&=\frac{\cos\theta-\sqrt{3}\sin\theta}{\sin2\theta}\\
&=\frac{2\cos(\theta+60^\circ)}{\sin2\theta}\\
&=\frac{2\cos70^\circ}{\sin20^\circ}\\
&=2
\end{align*}$$ |
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