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[几何] $ABCD$是$\odot O$外切四边形,求证$\angle EOB=\angle FOD$

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abababa Post time 2014-12-24 08:19 |Read mode
$ABCD$是$\odot O$外切四边形,切点分别为$A_1,B_1,C_1,D_1$,$AB,CD$交于$E$,$AD,BC$交于$F$,求证$\angle EOB=\angle FOD$
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爪机专用 Post time 2014-12-24 08:34
旧版论坛有椭圆的情形 kkkkuingggg.haotui.com/thread-993-1-1.html

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 Author| abababa Post time 2014-12-24 09:04
回复 2# 爪机专用
能请版主把那边的图发一下吗?我登录了旧版论坛,但是还是看不到图

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kuing Post time 2014-12-24 13:53
回复 3# abababa

嗯,那边的登录系统出了问题,我截一下图。

未命名.GIF

后面的内容就懒得贴了,看原贴。

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kuing Post time 2014-12-24 14:11
幸好改版来这边,最近那边好像老出问题。

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isee Post time 2014-12-24 16:06
回复 2# 爪机专用


    楼主的好些题目都属于竞赛几何范畴,是竞赛里的基本内容,如果扩展开,有很多东西可以说。

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 Author| abababa Post time 2014-12-26 09:09
回复 4# kuing
谢谢,这个等角性质学习了

手机版|悠闲数学娱乐论坛(第3版)

2025-3-5 10:56 GMT+8

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