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[函数] 一道函数题

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hjfmhh Post time 2015-6-25 15:05 |Read mode
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kuing Post time 2015-6-25 15:11
A、B 代 $x=0$ 和 $x=\pi/2$ 矛盾;
C 代 $x=\pm1$ 矛盾;
D 函数 $f(x)=\sqrt{x+1}$ 满足。

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guanmo1 Post time 2015-6-25 17:53
回复 2# kuing

简洁有力!这题虽然小巧,但考查函数的定义很到位。

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