Forgot password?
 Create new account
Search
View: 1508|Reply: 5

[不等式] 随便玩玩

[Copy link]

61

Threads

155

Posts

1243

Credits

Credits
1243

Show all posts

血狼王 Post time 2015-12-27 15:21 |Read mode
若$a+b+c=3$且$a,b,c$均为非负实数,求证
$$\frac{x^3}{x^2+2y^2}+\frac{y^3}{y^2+2z^2}+\frac{z^3}{z^2+2x^2}\geq 1+\frac{1}{2}|(x-y)(y-z)(z-x)|;$$
又,同条件下,求证
$$\frac{x^3}{2x^2+y^2}+\frac{y^3}{2y^2+z^2}+\frac{z^3}{2z^2+x^2}\geq 1+\frac{1}{14}|(x-y)(y-z)(z-x)|.$$

61

Threads

155

Posts

1243

Credits

Credits
1243

Show all posts

 Author| 血狼王 Post time 2015-12-27 16:12
求证对任意实数$x$均有:
$(1)$
$$-\frac{x^2}{32}\leq \frac{\sin x}{x}-\cos x\leq \frac{x^2}{3};$$
$(2)$
$$-\frac{x^4}{1050}\leq 1-\cos x-\frac{1}{2}x\sin x\leq \frac{x^4}{24}.$$

61

Threads

155

Posts

1243

Credits

Credits
1243

Show all posts

 Author| 血狼王 Post time 2015-12-28 17:45
对一切非负实数$x,y,z$,求证:
$$\frac{x^3}{(y-z)^2}+\frac{y^3}{(z-x)^2}+\frac{z^3}{(x-y)^2}\geq \sqrt{2(x^2+y^2+z^2)}.$$

61

Threads

155

Posts

1243

Credits

Credits
1243

Show all posts

 Author| 血狼王 Post time 2015-12-28 21:38
本帖最后由 血狼王 于 2015-12-29 16:15 编辑 若$0\leq z\leq y\leq x\leq 1$,求证:
$$\frac{5}{3}\leq x^y+y^z+z^x\leq 3.$$

61

Threads

155

Posts

1243

Credits

Credits
1243

Show all posts

 Author| 血狼王 Post time 2015-12-29 18:01
若$x,y,z$为非负实数,求证:
$$\frac{x^2}{y+2z}+\frac{y^2}{z+2x}+\frac{z^2}{x+2y}\geq \frac{x^3+y^3+z^3}{x^2+y^2+z^2}.$$

61

Threads

155

Posts

1243

Credits

Credits
1243

Show all posts

 Author| 血狼王 Post time 2015-12-29 18:02
以上题目大家任选一个来做,看看谁证得出来

手机版|悠闲数学娱乐论坛(第3版)

2025-3-6 17:34 GMT+8

Powered by Discuz!

× Quick Reply To Top Return to the list