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[函数] 有理函数$\{g>\Delta\}$ 区间的长度

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hbghlyj Post time 2024-2-22 05:51 |Read mode
设 $a_i, b_i(i=1,2,3, \cdots, n)$ 是满足 $a_1<b_1<a_2<b_2<\cdots<a_n<b_n$ 的实数,并令 $g$ 为有理函数
\[
g(x)=\prod_{k=1}^n \frac{x-a_k}{x-b_k} \quad(x \in \mathbb{R})
\]
$\Delta>1$
如何证明
$$(\Delta-1)|\{g>\Delta\}|=(\Delta+1)|\{g<-\Delta\}|=\sum_{k=1}^n\left(b_k-a_k\right) \text {. }$$
Untitled.png
例如,图中\[
|\{g>\Delta\}| =\sum_{k=1}^n\left(r_k-b_k\right) .
\]

Comments

图中 k_1,k_2,... 应该是 r_1,r_2,...  Post time 2024-2-22 05:58

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