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[不等式] 一个三元不等式

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lemondian Post time 2024-2-24 11:20 |Read mode
已知$a,b,c$为正实数,且$k\geqslant 2$,求证:$(a^k+2)(b^k+2)(c^k+2)\geqslant 3^{3-k}(a+b+c)^k$。

另外,这个不等式能不能推广到$n$元?

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kuing Post time 2024-2-24 17:55
当年我在《数学空间》2011 年第 2 期 P.37~38 曾得到如下推广:

那将 2 次方改为 `k\geqslant2` 次方(变量改为正数)时,由上述结论再加上幂平均,就有
\begin{align*}
\prod_{i=1}^n(x_i^k+n-1)&=\prod_{i=1}^n\Bigl(\bigl(x_i^{k/2}\bigr)^2+n-1\Bigr)\\
&\geqslant n^{n-2}\left(\sum_{i=1}^nx_i^{k/2}\right)^2\\
&=n^n\left(\left(\frac1n\sum_{i=1}^nx_i^{k/2}\right)^{2/k}\right)^k\\
&\geqslant n^n\left(\frac1n\sum_{i=1}^nx_i\right)^k\\
&=n^{n-k}(x_1+x_2+\cdots+x_n)^k.
\end{align*}

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