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hbghlyj 发表于 2022-7-28 09:30 |阅读模式
Show that $\Bbb Z$ with the 2-adic metric is not connected.

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Czhang271828 发表于 2022-7-29 13:49
Step 1. $\{d_p(x,y)\mid x,y\in \mathbb Q_p\}$ is discrete in $(\varepsilon,\infty)$ for each $\varepsilon >0$. Hence each open ball in $\mathbb Q_p$ is also closed.

Step 2. $\mathbb Z_p$ is open/closed ball in $\mathbb Q_p$. Therefore $(\mathbb Z_p,\|\cdot \|_p)$ is a topological subspace of $(\mathbb Q_p,\|\cdot \|_p)$.

Step 3. $\mathbb Q_p$ is totally disconnected. For each distinct $a,b\in \mathbb Q_p$, there exists an open/closed ball $B$ s. t. $a\in B$ and $b\notin B$. As a result, $\mathbb Q_p=B\dot\cup B^c$ is a disjoint union of two open sets.

We deduce that $\mathbb Q_p$ is totally disconnected, so is $\mathbb Z_p$.

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 楼主| hbghlyj 发表于 2022-8-6 10:44
Czhang271828 发表于 2022-7-29 06:49
Step 1. $\{d_p(x,y)\mid x,y\in \mathbb Q_p\}$ is discrete in $(\varepsilon,\infty)$ for each $\varep ...


Thanks for your reply. Please have a look at my work (for $p=2$):

\begin{array}l
B(0,1)=\{y:d_2(0,y)<1\}=\{y:2|y\}\\
B(1,1)=\{y:d_2(1,y)<1\}=\{y:2|y-1\}
\end{array}$B(0,1),B(1,1)$ are disjoint open sets and $\Bbb Z=B(0,1)∪B(1,1)$. So $\Bbb Z$ is not connected with the 2-adic metric.

Is the proof correct?

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Czhang271828 发表于 2022-8-6 15:12
hbghlyj 发表于 2022-8-6 10:44
Thanks for your reply. Please have a look at my work (for $p=2$):

\begin{array}l

Exactly correct. Your solution can be easily generalised to $\mathbb Z_p$ topology.

From my point of view, there is no need to explore more on $p$ -adic numbers untill you show some interests in field theory, especially the theory of Krull valuation.

It is highly recommended to learn sth about Monsky's thm, a perfect combination of Sperner's lemma and $p$ -adic theory, which is mainly about the impossibility of dissecting the square into an odd number
of triangles of equal area
. You can enjoy
无钱佮歹看、无样佮歹生、无汉草佮无文采、无学历佮无能力、无高度无速度无力度共闲无代志。(闽南话)
口号:疼惜生命,远离内卷。

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 楼主| hbghlyj 发表于 2024-10-5 20:26

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