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本帖最后由 hbghlyj 于 2022-9-9 20:07 编辑 根据Gauss's flux theorem, 二维的引力的模长与距离成反比, 三维的引力的模长与距离的平方成反比
vc.pdf page7
Example 4.1.
$\cdots\ \cdots$
In a planar universe, the gravitational force field exerted by a point mass concentrated at the origin has, according to Newtonian gravitational theory, magnitude proportional to† $1/r$, where $r = \| x \|$ is the distance to the origin, and is directed towards the origin. Thus, the vector field describing gravitational force has the form$$\tag{4.1}\mathbf{f}=-\gamma \frac{\mathbf{x}}{\|\mathbf{x}\|}=\left(\frac{-\gamma x}{\sqrt{x^{2}+y^{2}}}, \frac{-\gamma y}{\sqrt{x^{2}+y^{2}}}\right)^{T}$$where $γ > 0$ denotes the constant of proportionality, namely the product of the two masses times the universal gravitational constant. The same force law applies to the attraction, $γ > 0$, and repulsion, $γ < 0$, of electrically charged particles.
† In three-dimensional Newtonian gravity, $1/r$ is replaced by $1/r^2$
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the gradient of the logarithmic potential function
\[
u(x, y)=-\gamma \log r=-\frac{1}{2} \gamma \log \left(x^2+y^2\right)
\]
is the gravitational force (4.1) exerted by a point mass concentrated at the origin.
Newtonian gravity equation in a 2 dimensional world
Formally, you could write for circles around the point mass $C_1$ and $C_2$:
$$\int_{C_1}\vec F\left(r_1\right)\cdot \mbox{d}\vec s=\int_{C_2}\vec F\left(r_2\right)\cdot\mbox{d}\vec s$$
By rotational symmetry, this can be written as:
$$2\pi r_1 F_1=2\pi r_2 F_2 \Rightarrow F_2r_2=F_1r_1$$
See also. physics.stackexchange.com/questions/32779 |
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