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[几何] 求一个三角函数恒等式的解释

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郝酒 posted 2023-1-7 13:56 |Read mode
在做一道题时,得到了下面这个关系$(1\pm\sin\theta\pm\cos\theta)^2=2(1\pm\sin\theta)(1\pm\cos\theta)$,类似地,下面这个等式也成立$(1\pm\sin\theta\mp\cos\theta)^2=2(1\pm\sin\theta)(1\mp\cos\theta)$.
想问下上面的恒等式有没有类似于图解证明的解释,谢谢!

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kuing posted 2023-1-8 03:49
勉强构造出一个几何解释:
QQ截图20230108034621.png
如图,则整个大正方形面积为 `(1+\sin\theta+\cos\theta)^2`,黄色面积为 `(1+\sin\theta)(1+\cos\theta)`。
由 `\sin^2\theta+\cos^2\theta=1` 可知左上角、右下角俩小正方形面积之和等于中间的正方形面积,故黄色面积=白色面积,所以大正方形面积为黄色面积的两倍,即 `(1+\sin\theta+\cos\theta)^2=2(1+\sin\theta)(1+\cos\theta)`。

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original poster 郝酒 posted 2023-1-9 08:34 from mobile
谢谢ku版,其他的应该用诱导公式推吧

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yes  posted 2023-1-9 15:01

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