[数列] 一道数列题

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青青子衿 Posted 2013-11-23 12:44 |Read mode

$a_{n+1}=\frac{3^n+3a_n}{3^n-a_n}$

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kuing Posted 2013-11-23 13:11

这是原题？

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2025-6-6 01:52 GMT+8

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