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[数列] 数列命题初等求证

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hjfmhh posted 2023-7-5 23:12 |Read mode
348PI_CL70HF3S(H~OBF(HO.png

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Czhang271828 posted 2023-7-6 13:51
Last edited by Czhang271828 2023-7-6 19:42直接算. 不妨设存在 $m\in \mathbb N_+$ 使得 $\dfrac \beta m<1$. 计算得
\begin{align*}
&\left(1-\dfrac{\beta }{m+1}\right)\left(1-\dfrac{\beta }{m+2}\right)\cdots \left(1-\dfrac{\beta }{m+n}\right)\\[8pt]
=\,&\exp\sum _{k=1}^n\ln \left(1-\dfrac{\beta}{{m+k}}\right)\leq \exp \sum_{k=1}^n\dfrac{-\beta }{m+k}\\[8pt]
\leq \,&\exp \left(-\beta \cdot \int_{m+1}^{m+n+1}\dfrac{\mathrm dx}{x}\right)
\leq \exp \left(\beta\cdot  \ln\dfrac{m+1}{m+n+1}\right)\\[8pt]
=\,& \left(\dfrac{m+1}{m+n+1}\right)^\beta.
\end{align*}
从而 $b_n$ 被 $\dfrac{C}{n^\beta }$ 控制.

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original poster hjfmhh posted 2023-7-6 18:14
Czhang271828 发表于 2023-7-6 13:51
直接算. 不妨设存在 $m\in \mathbb N_+$ 使得 $\dfrac \beta m
倒数第二个小于等式反了

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谢谢, 调整了, 思路一样  posted 2023-7-6 19:41

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original poster hjfmhh posted 2023-7-6 18:47
Czhang271828 发表于 2023-7-6 13:51
直接算. 不妨设存在 $m\in \mathbb N_+$ 使得 $\dfrac \beta m
306bfa5834d7faee8867d6499a4c21a.jpg 按您的思路是不是可以这样理解

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是这样的, 这个思路应该挺常规的  posted 2023-7-6 19:43

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