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[不等式] 如何求该式子的取值范围?

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Rachmani Post time 2023-8-18 21:21 |Read mode
已知$\displaystyle x+y+\frac1x+\frac1y=5$,求$x+2y$的取值范围。用$\text{Aczel}$不等式待定参数,似乎遇到了高次方程......

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isee Post time 2023-8-18 21:47
不用怀疑了,就是“高次不可解型”,原问题是求 x+y
isee=freeMaths@知乎

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 Author| Rachmani Post time 2023-8-18 21:54 From the mobile phone
isee 发表于 2023-8-18 21:47
不用怀疑了,就是“高次不可解型”,原问题是求 x+y

好的,感谢!

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 Author| Rachmani Post time 2023-8-18 22:00
isee 发表于 2023-8-18 21:47
不用怀疑了,就是“高次不可解型”,原问题是求 x+y

请问有没有原问题的帖子?

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isee Post time 2023-8-18 22:24
Rachmani 发表于 2023-8-18 22:00
请问有没有原问题的帖子?

太平常了,随便搜索一下就是
isee=freeMaths@知乎

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