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[几何] 一个三角与圆锥曲线结合的题

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lemondian posted 2023-10-20 16:34 |Read mode
Last edited by kuing 2023-11-6 00:08 102001.jpg

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kuing posted 2023-10-20 17:02
Last edited by kuing 2023-11-6 00:10简单题,显然圆柱半径 `r=1`,所以 `b=r=1`,最高点比中心高 1,所以 `a=\sqrt{r^2+1}=\sqrt2`。

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