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[函数] 多项式 $z^n(z -2) -1$ 在 $|z|<1$ 中正好有 $n$ 个根。

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hbghlyj posted 2024-2-22 01:15 |Read mode
$n\ge1$, 多项式 $z^n(z -2) -1$ 在 $|z|<1$ 中正好有 $n$ 个根。

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