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[不等式] 如何证明四面体的陪位重心到各侧面的距离之和最小

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lihpb Posted at 2024-8-10 16:21:29 |Read mode
陪位重心即重心的等角共轭点

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爪机专用 Posted at 2024-8-10 17:25:26
Last edited by 爪机专用 at 2024-8-10 18:27:00到各侧面的距离之和最小的点应该是:最大的面所对的顶点。

你可以用一个直角四面体来验证一下,看看是倍位重心处小,还是直角顶点处小
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 Author| lihpb Posted at 2024-8-10 20:58:42 From the mobile phone
顶点和侧面上的点不算,只考虑四面体内的点

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爪机专用 Posted at 2024-8-10 22:37:28
lihpb 发表于 2024-8-10 20:58
顶点和侧面上的点不算,只考虑四面体内的点
……
如果某个顶点处的值小于倍位重心处,那就算是要求内部点,我也大可以让内点非常接近那个顶点,也肯定比倍位重心的小。
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