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[不等式] 证明二元函数的最小值点在$xy=0$上?

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hbghlyj Posted 2024-12-9 22:49 |Read mode
证明Schaffer function N. 4${\displaystyle f(x,y)=0.5+{\frac {\cos ^{2}\left[\sin \left(\left|x^{2}-y^{2}\right|\right)\right]-0.5}{\left[1+0.001\left(x^{2}+y^{2}\right)\right]^{2}}}}$只有4个全局最小值点,都在$xy=0$上?
schaffer4[1].png

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 Author| hbghlyj Posted 2024-12-9 22:52
WolframAlpha算出
download (3).gif

得出4个最小值点,都在$xy=0$上:

${\displaystyle {\text{Min}}={\begin{cases}f\left(0,1.25313\right)&=0.292579\\f\left(0,-1.25313\right)&=0.292579\\f\left(1.25313,0\right)&=0.292579\\f\left(-1.25313,0\right)&=0.292579\end{cases}}}$

如何证明它们是全局最小值点?

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