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[函数] 多项式恒等式$f(f-h)(f-2h)(f-3h)(f-4h)=g^2h^3$

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hbghlyj Posted 2024-12-10 03:43 |Read mode
Last edited by hbghlyj 2024-12-12 17:02若存在多项式$f(x),g(x),h(x)\inC[x]$使恒等式$$f(f-h)(f-2h)(f-3h)(f-4h)=g^2h^3$$成立,且$g(x)$不恒为0,则$\frac{f(x)}{g(x)},\frac{h(x)}{g(x)}$都是常数。



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