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[几何] 平行四边形ABCD ∡ADE=∡ECB ∡ABG=∡GCD 求证 ∡AEG+∡FGD=90°.

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hbghlyj posted 2025-1-5 11:54 |Read mode

平行四边形ABCD，中心为O，
E∈AB，∡ADE=∡ECB，
F∈CD，与 E 关于 O 对称，
G∈AD，∡ABG=∡GCD，
求证：∡AEG+∡FGD=90°.

平行四边形

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original poster hbghlyj posted 2025-1-5 12:12

已知条件为角相等

E∈AB，∡ADE=∡ECB，

G∈AD，∡ABG=∡GCD，

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original poster hbghlyj posted 2025-1-6 05:09

求证：∡AEG+∡DGF=90°.

如何证明呢？

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original poster hbghlyj posted 2025-1-7 16:35

頂一下

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