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[几何] 平行四边形ABCD ∡ADE=∡ECB ∡ABG=∡GCD 求证 ∡AEG+∡FGD=90°.

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hbghlyj Posted at 2025-1-5 11:54:58 |Read mode
平行四边形ABCD,中心为O,
E∈AB,∡ADE=∡ECB,
F∈CD,与 E 关于 O 对称,
G∈AD,∡ABG=∡GCD,
求证:∡AEG+∡FGD=90°.

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 Author| hbghlyj Posted at 2025-1-5 12:12:36

已知条件为 角相等

E∈AB,∡ADE=∡ECB,

G∈AD,∡ABG=∡GCD,

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 Author| hbghlyj Posted at 2025-1-6 05:09:06

求证:∡AEG+∡DGF=90°.



如何证明呢?

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 Author| hbghlyj Posted at 2025-1-7 16:35:04
頂一下

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