Forgot password?
 Register account
View 166|Reply 4

[不等式] 求一个三角函数的最小值

[Copy link]

413

Threads

905

Posts

110K

Credits

Credits
10989

Show all posts

lemondian Posted 2025-4-23 16:13 |Read mode
Last edited by hbghlyj 2025-4-24 00:28若$a,b>0,k>m,k,m\inN^*,x\in(0,\dfrac{\pi}{2})$,求$f(x)=\dfrac{a}{\sin^kx}+\dfrac{b}{\cos^mx}$的最小值。

686

Threads

110K

Posts

910K

Credits

Credits
91229
QQ

Show all posts

kuing Posted 2025-4-23 16:18
这种一看就知道一般情况根本没有解析解的啊

Comment

哪么换一种问法:$a,b,k,m$要满足什么条件,$f(x)$才有最小值?  Posted 2025-4-23 16:34

686

Threads

110K

Posts

910K

Credits

Credits
91229
QQ

Show all posts

kuing Posted 2025-4-23 16:38
lemondian 点评
哪么换一种问法:$a,b,k,m$要满足什么条件,$f(x)$才有最小值?
$a,b,k,m$ 取任意正数 `f` 都有最小值,我不是说他没最小值,而是最小值没法写出解析式。

Comment

对头,如果给定这几个参数的值是能写出最小值,我以为一般的情形可能归纳一下哩  Posted 2025-4-24 08:40

Mobile version|Discuz Math Forum

2025-5-31 11:00 GMT+8

Powered by Discuz!

× Quick Reply To Top Edit