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[不等式] 求一个三角函数的最小值

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lemondian posted 2025-4-23 16:13 |Read mode
Last edited by hbghlyj 2025-4-24 00:28若$a,b>0,k>m,k,m\inN^*,x\in(0,\dfrac{\pi}{2})$,求$f(x)=\dfrac{a}{\sin^kx}+\dfrac{b}{\cos^mx}$的最小值。

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kuing posted 2025-4-23 16:18
这种一看就知道一般情况根本没有解析解的啊

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哪么换一种问法:$a,b,k,m$要满足什么条件,$f(x)$才有最小值?  posted 2025-4-23 16:34

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kuing posted 2025-4-23 16:38
lemondian 点评
哪么换一种问法:$a,b,k,m$要满足什么条件,$f(x)$才有最小值?
$a,b,k,m$ 取任意正数 `f` 都有最小值,我不是说他没最小值,而是最小值没法写出解析式。

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对头,如果给定这几个参数的值是能写出最小值,我以为一般的情形可能归纳一下哩  posted 2025-4-24 08:40

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