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[概率/统计] 三种颜色的球摸完后的递推概率与条件概率

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其妙 posted 2025-5-16 17:56 |Read mode
Last edited by hbghlyj 2025-5-16 19:06一个不透明的袋子里边有大小形状完全相同的红,黄,蓝球各一个,每次从袋子中随机摸出一个球,记录颜色后放回。当三种颜色的小球均被摸出过时即停止摸球。记事件$A_i=$“第$i$次摸到红球”;$B_i =$“第$i$次摸到黄球”;$C_i $=“第$i$次摸到蓝球”;$D_i$=“摸完第$i$次球后就停止摸球”,求概率$P(D_n)$和条件概率$P(D_n|B_{n-1}C_{n-2})$的表达式.

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original poster 其妙 posted 2025-5-16 21:58
hbghlyj 发表于 2025-5-16 19:02
首先,我们考虑停止在第n次摸球的概率$P(D_n)$。当第n次摸球后停止,意味着前n次摸球中恰好收集到了三种颜 ...
某人的解法,对不对?如不对,错在哪
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这是对的。我错了。  posted 2025-5-17 09:31
妙不可言,不明其妙,不着一字,各释其妙!

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