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[几何] 八点共圆锥曲线,八线共点

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1+1=? posted 2025-6-23 02:39 from mobile |Read mode
Last edited by 1+1=? 2025-6-23 04:15证明:
两个锥线的四条公切线形成的完全四线形有三组对点,取一组对点中的一个顶点分别作这两个锥线的极线,两条极线相互交对方锥线于四个点,则该完全四线形另外两组对点和这四个点,8点共锥线。 1000093546.jpg
下图隐藏了一条公切线,根据命题可知这条公切线就是绿色虚线轨迹和二直线$AB,AC$的交点连线。
1000093532.png

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original poster 1+1=? posted 2025-6-23 04:15 from mobile
证明二:
在复射影平面上,上述八点所共的锥线和原先两个锥线一共有8个交点,连接相对交点形成的四条直线以及公切线完全四形的对角线以及两个锥线的根轴,八线共点。
如图 1000093556.jpg

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