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[函数] 一道典型高考题学生解法怎么修正

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hjfmhh posted 2025-7-23 15:40 |Read mode
1753254046840.jpg 这个2020年的高考题解法很多,一个学生的解法如上,感觉逻辑比较清晰的,在最后说2a+1<=x4<=2时,好像有点问题,怎么修正?谢谢

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战巡 posted 2025-7-23 15:53
Last edited by 战巡 2025-7-23 21:11逻辑清晰??????
结果一看就不对啊,这玩意哪来的上限?

而且整出三阶导,还如此长篇大论,几个意思?

当$x>0$时
\[e^x+ax^2-x\ge\frac{x^3}{2}+1\]
\[a\ge \frac{2-2e^x+2x+x^3}{2x^2}\]

\[\frac{d}{dx} \frac{2-2e^x+2x+x^3}{2x^2}=\frac{(x-2)(1+x+\frac{x^2}{2}-e^x)}{x^3}\]
这里面
\[e^x\ge 1+x+\frac{x^2}{2}\]
是大家都熟知的结论,因此其零点就只有$x=2$,验证为极大值,故此
\[a\ge \frac{2-2e^x+2x+x^3}{2x^2}|_{x=2}=\frac{7-e^2}{4}\]

最后验证$x=0$也成立,这就完事了啊

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original poster hjfmhh posted 2025-7-23 22:22
战巡 发表于 2025-7-23 15:53
逻辑清晰??????
结果一看就不对啊,这玩意哪来的上限?

嗯,这些方法知道。学生的分类讨论也是可以的,只是第三类讨论最后环节有点问题,能不能修正?

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