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[不等式] 柯西很诱人,可惜,想不出

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realnumber Posted at 2013-8-29 12:21:45 |Read mode
几何牛1.png 代数有些笨拙1.png

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reny Posted at 2013-8-29 12:25:14
柯西之后不就是取等条件吗?

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 Author| realnumber Posted at 2013-8-29 12:30:36
回复 2# reny


    但得出个恒成立,不在取等条件也没矛盾啊~~,

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kuing Posted at 2013-8-29 16:36:23
换个方向吧
\begin{align*}
25&=3\sqrt{41-40\cos\alpha}+4\sqrt{34-30\sin\alpha} \\
&=\sqrt{(15\sin\alpha)^2+(15\cos\alpha-12)^2} +\sqrt{(20\cos\alpha)^2+(12-20\sin\alpha)^2} \\
&\geqslant\sqrt{(15\sin\alpha+20\cos\alpha)^2+(15\cos\alpha-20\sin\alpha)^2} \\
&=\sqrt{15^2+20^2} \\
&=25,
\end{align*}
故只能取等号,而等号成立当且仅当
\[\frac{15\sin\alpha}{20\cos\alpha}=\frac{15\cos\alpha-12}{12-20\sin\alpha},\]
化简为
\[3\sin\alpha+4\cos\alpha=5,\]
故 $\sin\alpha=3/5$。

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心语 Posted at 2013-9-3 18:53:02
三解征解24.JPG 三解征解241.JPG

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