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[不等式] 一道不等式(四元)

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longzaifei posted 2014-3-7 13:09 |Read mode
设$a,b,c,d \ge 0 ,a^3+b^3+c^3+d^3=1$,求证 :\[ \dfrac{1}{1-bcd}+\dfrac{1}{1-cda}+\dfrac{1}{1-dab}+\dfrac{1}{1-abc} \le \dfrac{16}{3}   \]

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其妙 posted 2014-3-7 18:43

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