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几道三角函数方程

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青青子衿 Posted 2014-3-9 09:50 |Read mode
$\cos x=\sin3x$
$\cos2x=\sin3x$
$\cos4x=\sin3x$
QQ图片20140309092731.jpg

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realnumber Posted 2014-3-19 22:09
回复 1# 青青子衿
$\cos{x}=\sin{3x}=\cos{(\frac{\pi}{2}-3x)}$
得到$x+2k\pi=\frac{\pi}{2}-3x或-x+2k\pi=\frac{\pi}{2}-3x,k\in{Z}$
解出x.
其余类似.

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isee Posted 2014-3-31 14:24
最后那个三次方程的根,直接韦达定理不就OK了么

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