Forgot password?
 Create new account
View 1655|Reply 1

[数列] 等差数列与等比数列

[Copy link]

93

Threads

88

Posts

983

Credits

Credits
983

Show all posts

aishuxue Posted at 2014-3-26 21:18:54 |Read mode
1.png

84

Threads

436

Posts

5432

Credits

Credits
5432

Show all posts

tommywong Posted at 2014-3-26 22:50:15
$\frac{a+2d}{a+d}\le \frac{a+d}{a} \Leftrightarrow \frac{a_{2n+1}}{a_{2n}} \le \frac{a_{2n}}{a_{2n-1}}$

$\frac{ar^2}{ar}\le \frac{ar}{a} \Leftrightarrow \frac{a_{2n+2}}{a_{2n+1}}=\frac{a_{2n+1}}{a_{2n}} \le \frac{a_{2n}}{a_{2n-1}}$

$a_1,a_2,a_3$等差,d>0,$\frac{a_3}{a_2}<\frac{a_2}{a_1}$(不取等)

手机版Mobile version|Leisure Math Forum

2025-4-22 03:46 GMT+8

Powered by Discuz!

× Quick Reply To Top Return to the list