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[不等式] (z)一个三角函数不等式

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realnumber Posted 2014-4-8 13:46 |Read mode
山西-宋?军
QQ图片20140408103402-----啊2.jpg

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kuing Posted 2014-4-8 13:59
holder\[(\cos^2b+\sin^2b)\left( \frac{\sin^3a}{\cos b}+\frac{\cos^3a}{\sin b} \right)^2\geqslant (\sin^2a+\cos^2a)^3\]

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kuing Posted 2014-4-8 14:07
如果不接受 holder,总可以改写。
\[\frac{\sin^3a}{\cos b}+\frac{\sin^3a}{\cos b}+\cos^2b\geqslant 3\sin^2a\]

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 Author| realnumber Posted 2014-4-8 14:17
明白了

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