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[不等式] 不等式恒成立

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007 posted 2014-5-13 08:41 |Read mode
设$x,y,z$是三角形的三边长且$x+y+z=1$,求实数$\lambda$的最小值,使$\lambda (xy+yz+zx)\geqslant 3(\lambda +1)xyz+1$恒成立.
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kuing posted 2014-5-13 12:45
齐次化,内切圆代换,然后用Schur分拆(wenku.baidu.com/link?url=3a3KkWebYh_vTBsNBjTn … wEoLEn4u7gb0HndcZvBO 定理3)

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original poster 007 posted 2014-5-16 14:11
回复 2# kuing

抱歉直到现在才回复,那天发完帖子就断网了,刚刚才修复。谢谢,在你的提示下,已经解出来了……

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hbghlyj posted 2023-4-18 07:31

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kuing posted 2023-4-18 12:19
hbghlyj 发表于 2023-4-18 07:31
对不起,该文档已被删除
当时贴的文章应该是《用Schur分拆方法证明不等式竞赛题》(姚 勇 陈胜利)
搜一下还是能找到的:max.book118.com/html/2015/0506/16513174.shtm

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