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[数论] 若$\varphi(n)=2$,求证$n \le 6$

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abababa posted 2014-7-6 19:18 |Read mode
$\varphi(n)$是欧拉函数,即不大于$n$且与$n$互素的正整数的个数,若$\varphi(n)=2$,求证$n \le 6$

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tommywong posted 2014-7-6 20:11
$p>4,\varphi(p^k)=p^{k-1}(p-1)>3$

$\varphi(2^k)=2^{k-1},k \le 2$

$\varphi(3^k)=3^{k-1}2,k \le 1$

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original poster abababa posted 2014-7-7 06:24
回复 2# tommywong
这个第一行的公式条件不对吧,只有当$p$是素数时才成立,这里$n$不一定是素数。
例如$\varphi(6)=2$,这三行里就都没有体现出来。

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tommywong posted 2014-7-7 06:45
回复 3# abababa

$\varphi (n)$是积性函数

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original poster abababa posted 2014-7-7 08:10
回复 4# tommywong
谢谢,我明白2楼的意思了。

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hbghlyj posted 2023-5-15 19:45
abababa 发表于 2014-7-6 12:18
若$\varphi(n)=2$,求证$n \le 6$ .

$\iff a(2)=6$
$a(n)$ is the largest $x$ such that $\varphi(x)=n$. A006511

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