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[数论] 如何判断二次多项式是否存在平方数

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tommywong Posted at 2014-7-12 11:17:54 |Read mode

$y=x^2+1=2,5,10,17,...$
$y=x^2+3=4,7,12,19,...$

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caijinzhi Posted at 2014-7-12 14:35:53

二次剩余！？

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realnumber Posted at 2014-7-12 21:24:08

回复 2# caijinzhi

1楼举的例子，如果$a>b>1,a,b\in N$,那么$a^2-b^2=(a-b)(a+b)\ge3$,
所以4是唯一一个了．

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