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[数论] 如何判断二次多项式是否存在平方数

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tommywong posted 2014-7-12 11:17 |Read mode
$y=x^2+1=2,5,10,17,...$
$y=x^2+3=4,7,12,19,...$
现充已死,エロ当立。
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caijinzhi posted 2014-7-12 14:35
二次剩余!?

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realnumber posted 2014-7-12 21:24
回复 2# caijinzhi

1楼举的例子,如果$a>b>1,a,b\in N$,那么$a^2-b^2=(a-b)(a+b)\ge3$,
所以4是唯一一个了.

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