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[数列] zt:一个递推数列

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realnumber posted 2014-7-30 10:28 |Read mode

江苏南京王浩杰：数列{$a_n$},满足$a_1=2,a_{n+1}=2a_n^2-1$,求通项公式.
$a_1=\frac{e^{x_{0}}+e^{-x_0}}{2},a_n=\frac{e^{x_02^{n-1}}+e^{-x_02^{n-1}}}{2}$,符合条件.

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original poster realnumber posted 2014-7-30 10:32

kk论坛论坛上好象谁这么写过？

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战巡 posted 2014-7-30 10:48

回复 1# realnumber

pep.com.cn/rjwk/gzsxsxkj/2011/sxkj2/2jjp/2011 … 20110402_1031466.htm
参见例3.1.2

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original poster realnumber posted 2014-7-30 11:27

恩，就是,以前只在kk论坛上看到一部分.

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