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[组合] 一次不定方程的解数(练习用)

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tommywong posted 2014-8-5 11:16 |Read mode
设$a_i$为正整数,求以下不定方程的解数:
1.$a_1+2a_2=1000$
2.$2a_1+3a_2=1000$
3.$a_1+a_2+2a_3=1000$
4.$a_1+a_2+2a_3+4a_4=1000$
现充已死,エロ当立。
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original poster tommywong posted 2014-8-7 09:12
on9新方法$1+x+x^2+x^3+...=(1+x+...+x^{k-1})(1+x^k+x^{2k}+...)$

$(1+x+x^2+...)(1+x^2+x^4+...)=(1+x)(1+x^2+x^4+...)^2$

$=(1+x)(1+2x^2+3x^4+...)=1+x+2x^2+2x^3+3x^4+3x^5+...$

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