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[几何] 矩形的三个顶点处的直角三角形的面积为3,5,8,求矩形面积

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其妙 Post time 2014-8-26 21:47 |Read mode
1博客图片.jpg
以前曾经做过,现在找不到链接了。
妙不可言,不明其妙,不着一字,各释其妙!

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地狱的死灵 Post time 2014-8-26 22:09
设AD=a,AB=b
BE=6/b,DF=10/a
(b-10/a)(a-6/b)=16,
即可解出ab

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