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[不等式] 求等号何时成立

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isee posted 2014-9-4 08:41 |Read mode
证明:对任意实数$x,y,z$有\[x^4(1+y^4)+y^4(1+z^4)+z^4(1+x^4)\geqslant 6x^2y^2z^2,\]并求等号何时成立。

PS:哈哈,我能理解的不等式就这程度,不能再难了,再难,我自己就不会了。

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realnumber posted 2014-9-4 09:13
$1+y^4\ge 2y^2,$,...
只需要证明$x^4y^2+y^4z^2+z^4x^2\ge 3x^2y^2z^2$
取等条件是$x^2=y^2=z^2=1$

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爪机专用 posted 2014-9-4 09:38
我擦这也太水了吧���
I am majia of kuing

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original poster isee posted 2014-9-13 22:23
回复 2# realnumber


    哈哈,均值出手即可……

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