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[函数] 一个函数题3

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转化与化归 posted 2013-9-25 17:57 |Read mode
Last edited by hbghlyj 2025-5-4 00:30函数 $f(x)=(x-2)^3, g(x)=x \cos \pi x, h(x)=f(x)-g(x)$,证明:函数 $y=h(x)$ 在区间 $\left(1, \frac{3}{2}\right)$ 存在唯一零点.
本题画图很容易得到结论,纯代数证明怎么写呢?

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其妙 posted 2013-9-25 18:15
回复 1# 转化与化归
帮你把原题和解析传过来,这样别人就有资料解决你的问题了
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