Forgot password?
 Register account
View 2608|Reply 1

[函数] 一个函数题3

[Copy link]

29

Threads

70

Posts

647

Credits

Credits
647

Show all posts

转化与化归 Posted 2013-9-25 17:57 |Read mode
Last edited by hbghlyj 2025-5-4 00:30函数 $f(x)=(x-2)^3, g(x)=x \cos \pi x, h(x)=f(x)-g(x)$,证明:函数 $y=h(x)$ 在区间 $\left(1, \frac{3}{2}\right)$ 存在唯一零点.
本题画图很容易得到结论,纯代数证明怎么写呢?

84

Threads

2336

Posts

110K

Credits

Credits
13076

Show all posts

其妙 Posted 2013-9-25 18:15
回复 1# 转化与化归
帮你把原题和解析传过来,这样别人就有资料解决你的问题了
blog图片博客.jpg

Mobile version|Discuz Math Forum

2025-6-6 01:59 GMT+8

Powered by Discuz!

× Quick Reply To Top Edit