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longzaifei Post time 2014-10-6 10:01 |Read mode
本帖最后由 longzaifei 于 2014-10-6 10:07 编辑 Solve the following system: $2\sqrt{2x+6}=y^2-6, 2\sqrt{2y+6}=z^2-6,2\sqrt{2z+6}=x^2-6$.

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其妙 Post time 2014-10-6 11:10
数据不舒服,用均值不等式?

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wzxsjz Post time 2014-10-6 14:18
函数反函数

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wzxsjz Post time 2014-10-22 18:57
能证明$x \geqslant0 $吗?

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kuing Post time 2014-10-22 21:23
能证明$x \geqslant0 $吗?
wzxsjz 发表于 2014-10-22 18:57

不能,事实上有负的解 $x=y=z=-1-\sqrt3$

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