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[不等式] 一个经典不等式的证明

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wzxsjz posted 2014-12-6 11:15 |Read mode
已知$x^3+y^3=2$,求证:$x+y\leqslant2$,
谁知道最近什么考试用过该题,请出手相助,以满足在下的好奇之心。谢谢!

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kuing posted 2014-12-6 12:03
又不是什么特别的题,知道什么考试用过它有啥意思,还不如搞点变式或推广什么的

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kuing posted 2014-12-6 12:06
想起在《数学空间》2011第3期第5页里我就写过证法及推广

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original poster wzxsjz posted 2014-12-6 12:44
学习了,

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realnumber posted 2014-12-9 10:14
那三个或以上变量呢

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realnumber posted 2014-12-9 10:16
比如\[x^3+y^3+z^3=3,x>0,y>0,z>0,则x+y+z\le3?\]

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爪机专用 posted 2014-12-9 12:14
回复 6# realnumber
正数就太简单了,上面说的都是实数范围

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战巡 posted 2014-12-10 02:21
回复 7# 爪机专用


管它是不是正数,不都是琴生直接秒的节奏........

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original poster wzxsjz posted 2014-12-10 12:10
不像君说的那样简单

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kuing posted 2014-12-10 13:05

管它是不是正数,不都是琴生直接秒的节奏........
战巡 发表于 2014-12-10 02:21
错了,实数范围的话,那些函数就不保凸了,不能琴生

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kuing posted 2014-12-10 13:48
事实上,6楼的三元推广如果将 x,y,z>0 改为 x,y,z 属于 R 的话,就是不成立的。
例如 $x=y=5$, $z=-\sqrt[3]{247}$,它满足 $x^3+y^3+z^3=3$,但 $x+y+z=10-\sqrt[3]{247}\approx 3.7$。

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