Forgot password?
 快速注册
Search
View: 1803|Reply: 3

[几何] 以两边为直角边向外作等腰直角三角形,求证$AD \perp B_2C_2$

[Copy link]

413

Threads

1558

Posts

110K

Credits

Credits
11498

Show all posts

abababa Post time 2014-12-26 22:34 |Read mode
以$\triangle ABC$的边$AB,AC$为直角边向外作等腰直角三角形$\triangle ABB_1, ACC_1$,$AB_1,AC_1$的中点分别是$B_2,C_2$,$BC_2,CB_2$交点为$D$,求证$AD \perp B_2C_2$
无标题.png

730

Threads

110K

Posts

910K

Credits

Credits
93633
QQ

Show all posts

kuing Post time 2014-12-26 23:08

830

Threads

4866

Posts

310K

Credits

Credits
36180

Show all posts

isee Post time 2014-12-26 23:10

413

Threads

1558

Posts

110K

Credits

Credits
11498

Show all posts

 Author| abababa Post time 2014-12-29 15:18
谢谢,原来有更一般的情况

手机版|悠闲数学娱乐论坛(第3版)

2025-3-5 10:47 GMT+8

Powered by Discuz!

× Quick Reply To Top Return to the list