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[函数] 函数

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hjfmhh Posted 2015-3-11 09:56 |Read mode
Last edited by hbghlyj 2025-4-1 05:428.定义在实数集 $R$ 上的函数 $f(x)$ ,对任意 $x \in R$ 和常数 $a>0$ ,都有 $f(x+a)=\frac{1}{2}-\sqrt{f(x)-f^2(x)}$ ,若函数 $f(x)$ 的值域为 $M$ ,则下列成立的是
A.$\frac{\sqrt{2}}{3} \in M$
B.$\frac{\pi}{5} \in M$
C.$\frac{\sqrt{2}}{2} \in M$
D.$\frac{\pi}{3} \in M$

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战巡 Posted 2015-3-11 10:36
回复 1# hjfmhh


你这$f(x)$不就一个常函数么...
对任意$a>0$都有$f(x+a)=...$,也就是$f(x+a)=c$
然后可知$f(x)=\frac{1}{4}(2-\sqrt{2})$

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 Author| hjfmhh Posted 2015-3-11 11:56
常数a

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tommywong Posted 2015-3-11 13:19
A
$f(x)\le \cfrac{1}{2}$

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战巡 Posted 2015-3-11 14:12
回复 3# hjfmhh

对任意常数$a$

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kuing Posted 2015-3-11 14:27
居然变成语文问题……

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