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[函数] 求解一带参数的分式型三角函数的最大值(难)

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青青子衿 Posted at 2013-10-1 13:13:48 |Read mode
一带参数的分式型三角函数的最大值
241f95cad1c8a786627971e56609c93d71cf508d.jpg
其中a,b>0

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kuing Posted at 2013-10-1 13:18:55
何必扯上三角函数?换个元 $\cos x=t\in(0,1)$ 就变成 $g(t)=(1-t)t^2/(at^2+b)$,求导后出现三次方程,估计没什么简单结果。
PS、题外话:有没有考虑试一下用代码来写公式?这样可以省掉贴图

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睡神 Posted at 2013-10-1 17:43:20
目测$a=4b$时有简单结果…
除了不懂,就是装懂

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