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[几何] 请教一道向量题

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wzxsjz posted 2015-9-23 01:12 |Read mode
以正多面体的中心为始点,各个顶点为终点的向量的和为零向量
求证明,谢谢,

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kuing posted 2015-9-23 01:29
正多面体只有正四面体、正六面体(正方体)、正八面体、正十二面体、正二十面体五种,
记 $L$ 为过正多面体中心及任一面中心的直线,不难证明这五种正多面体均能绕 $L$ 旋转一定角度 $\theta$($0<\theta<360\du$)使之与原先重合,这说明,那些向量的和绕 $L$ 旋转 $\theta$ 角后亦与原先重合,这显然只能为零向量。
存★在!! posted 2015-9-23 10:08
明显质量中心受力平衡,难道还想推翻牛顿力学?

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original poster wzxsjz posted 2015-9-25 08:15
谢谢二位

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