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[几何] 立体几何题:异面直线最大距离问题

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goft posted 2016-2-2 11:01 |Read mode

感觉不好处理

感觉不好处理

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longzaifei posted 2016-2-3 10:14
固定$A,D$两点,因为$\dfrac{AB}{BD}=\dfrac{AC}{CD}=2$,那么$B,C$两点就是在一个阿氏球面上(类比),$A,D$在球的直径所在直线上,利用几何图像,可以得到异面直线$AD,BC$的最大距离为$\sqrt{15} $,所以答案是 $2\sqrt{15}$

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original poster goft posted 2016-2-3 17:02
谢谢指点

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