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[数论] 一道不定方程的解

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力工 Posted 2016-5-3 16:14 |Read mode
求不定方程的有理解$ (x,y) $:
$ 1/\sqrt{x-1}-1/\sqrt{x+1}=\sqrt{y/(y^2-1)} $.
此题较难,已知两组解$ (\frac{5}{3},3 $)与$( \frac{5}{3},-\frac{1}{3}) $,大神们再做做。

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isee Posted 2016-5-26 23:12
求不定方程的有理解$ (x,y) $:
$ 1/\sqrt{x-1}-1/\sqrt{x+1}=\sqrt{y/(y^2-1)} $.
此题较难,已知两组解$ ( ...
力工 发表于 2016-5-3 16:14
楼主搞定过程没?丢来学习下

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