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[不等式] 转发：2016_5_21

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realnumber posted 2016-5-21 09:32 |Read mode

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\[\frac{1}{m^3}\le \frac{1}{2}(\frac{1}{(m-0.5)^2}-\frac{1}{(m+0.5)^2})\]

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2025-6-8 21:04 GMT+8

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