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original poster
isee
posted 2016-6-10 20:56
记$\vv {BD}=\vv a,\vv {DF}=\vv b$,则$$\vv {BA} \cdot \vv {CA}=(\vv a+3\vv b)(-\vv a+3\vv b)=9\vv b^2-\vv a^2=4.$$
$$\vv {BF} \cdot \vv {CF}=(\vv a+\vv b)(-\vv a+\vv b)=\vv b^2-\vv a^2=-1.$$
两式可求出$\vv b^2,\vv a^2$具体值。
而$$\vv {BE}\cdot \vv {CE}=(\vv a+2\vv b)(-\vv a+2\vv b)=4\vv b^2-\vv a=\cdots=\frac 78.$$ |
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