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[组合] (zt)依次绝对值差,构造最大最小

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realnumber posted 2016-6-13 14:16 |Read mode
北京赵-(52-----8) 2016-06-12 16:14:04
QQ图片20160613141130-1.jpg
浙江杭州骆来根(37----99) 2016-06-13 07:59:08
$a^2-(a+1)^2-(a+2)^2+(a+3)^2-(a+4)^2+(a+5)^2+(a+6)^2-(a+7)^2=0$,所以最小值是0.
求最大值也就是求最小值,先考虑$0^2,1,^2,2^2,3^2,…,2015^2$的代数和为0,再添上$2016^2$,结果为$2016^2$.显然不大于$2016^2$,因此最大值为$2016^2$.

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