Forgot password?
 Create new account
View 2509|Reply 3

[函数] 一类与声音有关的三角函数

[Copy link]

462

Threads

969

Posts

9934

Credits

Credits
9934

Show all posts

青青子衿 Posted at 2013-10-13 14:12:11 |Read mode
1.jpg
2.jpg
3.jpg
如何求其单调区间、周期、值域?
拜托kuing整理了,谢谢!

65

Threads

414

Posts

3556

Credits

Credits
3556

Show all posts

Tesla35 Posted at 2013-10-13 14:19:56
Last edited by Tesla35 at 2013-10-13 14:40:00没有实用意义吧,这是傅里叶级数的前几项嘛

700

Threads

110K

Posts

910K

Credits

Credits
94172
QQ

Show all posts

kuing Posted at 2013-10-13 20:33:36
求导不就好了,请动手

462

Threads

969

Posts

9934

Credits

Credits
9934

Show all posts

 Author| 青青子衿 Posted at 2013-10-26 10:46:09
$f(x)=\sin x+\frac{1}{2}\sin2x+\frac{1}{3}\sin3x$
$f'(x)=\cos x+\cos2x+\cos3x=\cos x+2\cos^2x-1+4\cos^3x-3\cos x=2\cos^2x(2\cos x+1)-(2\cos x+1)=(2\cos^2x-1)(2\cos x+1)$
$f(x)=\sin x+\frac{1}{2}\sin2x+……+\frac{1}{n}\sin nx$
$f'(x)=\cos x+\cos2x+……+\cos nx=\frac{1}{2\sin\frac{x}{2}}(2\cos x\sin\frac{x}{2}+2\cos2x\sin\frac{x}{2}+……+2\cos nx\sin\frac{x}{2})=\frac{1}{2\sin\frac{x}{2}}[(\sin\frac{x}{2}-\sin\frac{3x}{2})+(\sin\frac{3x}{2}-\sin\frac{5x}{2})+……+(\sin\frac{2n-1}{2}x-\sin\frac{2n+1}{2}x)]=\frac{1}{2\sin\frac{x}{2}}(\sin\frac{x}{2}-\sin\frac{2n+1}{2}x)=\frac{\sin\frac{nx}{2}\cos\frac{n+1}{2}x}{sin\frac{x}{2}}$

手机版Mobile version|Leisure Math Forum

2025-4-21 14:24 GMT+8

Powered by Discuz!

× Quick Reply To Top Return to the list