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[函数] 求a的取值范围

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realnumber posted 2016-11-30 19:15 |Read mode
$f(x)=ax^2-1$,若{x│$f(x)=x$}={x│$x=f(f(x))$}≠Ф,求实数a的取值范围.













考虑$y=ax^2-1$与$x=ay^2-1$图像交点情况,$y=f(x)$与$y=x$交点处的导数为-1,图像法解的,我也说不好理由.

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